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A phasor current 25 408 A has complex frequency s 2 j3 s 1 . What is the magnitude of i t at t 0:2 s Ans: 4:51 A Calculate the impedance Z s for the circuit shown in Fig. 8-32, at (a) s 0; b s j1 rad/s, (c) s j2 rad/s, (d) jsj 1. Ans: a 1

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The circuit of Fig. 8-15(a) is driven by a sinusoidal source vS . (a) Sketch the asymptotic Bode plot Mdb only) associated with the Laplace-domain transfer function T s Vo =VS . (b) Use Table 8-1 to correct asymptotic plot, so as to show the exact Bode plot.

Performing a translation Let rectangle ABCD be formed by A( 1, 4), B( 1, 3), C(3, 3), and D(3, 4). Graph rectangle ABCD and its image under the following translations: (a) P(x, y) A Pr(x (b) P(x, y) A Ps(x (c) P(x, y) A P-(x

; b 1:58 18:438

Thus, in Fig. 2-27, j a > j b; this follows from Principle 4, since j a and j b are supplements of the same angle, j c.

RL _

; c 1:84 12:538

Fig. 2-27

Fig. 8-32

_ (a)

Fig. 8-33

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2.10 Applying basic theorems: principles 1 to 5 State the basic angle theorem needed to prove j a > j b in each part of Fig. 2-28.

_ 20

The voltage source in the s-domain circuit shown in Fig. 8-33 has the time-domain expression vi t 10e t cos 2t Obtain io t . Ans: 7:07e cos 2t 98:138

Fig. 2-28

In the time domain, a series circuit of R, L, and C has an applied voltage vi and element voltages vR , vL , and vC . Obtain the voltage transfer functions (a) VR s =Vi s , (b) VC s =Vi s :

s (a) Since AB and AC are straight lines, j a and j b are straight j. Hence, j a > j b. are congruent.

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Using the result of Problem 8.2, we recognize (2) as the combination of a rst-order lag, a constant gain, and a zero of multiplicity 1. The components of the asymptotic Bode plot are shown dashed in Fig. 8-15(b), and the composite is solid. For purposes of illustration, it was assumed that 1= C RL RS > 1, which is true in most cases. (b) The correction factors of Table 8-1 lead to the exact Bode plot as drawn in Fig. 8-15(b).

Ans:

s (b) Since BA ' AD and BC ' CD, j a and j b are rt. j. Hence, j a > j b. Ans. All right angles are congruent.

CHAP. 8]

Obtain the network function H s for the circuit shown in Fig. 8-34. Ans: s 7 j2:65 s 7 j2:65 s 2 s 4

(c) Since AB ' BC, j B is a rt. j , making j b the complement of j 1. Since j a is the complement of j 1, j a > j b. Ans. Complements of the same angle are congruent.

Sketch the asymptotic Bode plot (Mdb only) associated with the output-to-input voltage ratio of the circuit in Fig. 8-16(a).

Fig. 8-34 8.35 Construct the s-plane plot for the transfer function of Problem 8.34. Ans: See Fig. 8-35. 7:02 9:0 2:86 38:918 3:50 51:418

The statements A heated metal expands and If a metal is heated, then it expands are two forms of the same idea. The following table shows how each form may be divided into its two important parts, the hypothesis, which tells what is given, and the conclusion, which tells what is to be proved. Note that in the if-then form, the word then may be omitted. Hypothesis (What is given) Hypothesis is subject: A heated metal Hypothesis is if clause: If a metal is heated Conclusion (What is to be proved) Conclusion is predicate: expands Conclusion is then clause: then is expands

Fig. 8-35 8.36 Obtain H s Vi s =Ii s for the circuit shown in Fig. 8-36 and construct the pole-zero plot. s s2 1:5 : s2 1

_ (a)

Form Subject-predicate form: A heated metal expands. If-then form: If a metal is heated, then it expands.

Ans:

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